NTA Abhyas JEE Main2020MathematicsDefinite IntegrationPractice
The value of the integral I = ∫ 0 π 2 sin 3 x - cos 3 x 1 + sin 6 x cos 6 x d x is equal to
Correct answer
0
Step-by-step solution
Applying a + b - x property, I = ∫ 0 π 2 cos 3 x - sin 3 x 1 + cos 6 x sin 6 x ⇒ I = - I ⇒ 2 I = 0 ⇒ I = 0