Quantrex Quantrex AcademyJEE · NEET · NDA PYQs with solutions Open app
NTA Abhyas JEE Main2020MathematicsDefinite IntegrationPractice

Consider the integral A = ∫ 0 1 e x - 1 x d x and B = ∫ 0 1 x e x - 1 d x . Then, which of the following is incorrect?

Options

  1. AB < 1
  2. BA > 1
  3. CB > A
  4. DA > 1 2

Correct answer

C. B > A

Step-by-step solution

As, e x - 1 &#62; x &#160; &#8704; x &#8712; 0 , &#8734; &#8756; e x - 1 x &#62; 1 Hence, A = &#8747; 0 1 e x - 1 x d x &#62; &#8747; 0 1 1 d x &#8658; A &#62; 1 And, B = &#8747; 0 1 x e x - 1 d x &#60; &#8747; 0 1 1 d x &#8658; B &#60; 1 &#8756; &#160; B &#60; 1 &#60; A

Practice Definite Integration on Quantrex Academy →

More from Definite Integration

The value of the definite integral ₀² 1 3^ x+3 2 , dx is 2026The value of the integral ₀² x(x^2+x+1) ( x+1 )( x^4+x^2+1 ) , dx is equal to: 2026If _ /6 ^ /4 ( (x- 3 ) (x+ 3 )+1 )dx = _e( 3 -1) , then 9 ^2 is equal to ________. 2026Let A = bmatrix 1 & 3 & -1 2 & 1 & 0 & 1 & -1 bmatrix be a singular matrix. Let f(x) = ₀^x (t^2 + 2t + 3) ,dt , x [1, ] . If M and m are respectively the maximum and the minimum va 2026Let f: R R be such that f(xy) = f(x)f(y) , for all x, y R and f(0) 0 . Let g: [1, ) R be a differentiable function such that x^2 g(x) = ₁^x (t^2 f(t) - tg(t)) ,dt . Then g(2) is eq 2026The value of the integral _ -1 ¹ ( x^3 + |x| + 1 x^2 + 2|x| + 1 ) dx is equal to : 2026The value of the integral _ - /4 ^ /4 ( 32 ^4 x 1 + e^ x )dx is: 2026Let (2^ 1-a + 2^ 1+a ) , f(a) , (3^a + 3^ -a ) be in A.P. and be the minimum value of f(a) . Then the value of the integral _ _e( -1) ^ _e( ) dx (e^ 2x - e^ -2x ) is : 2026 Full Definite Integration list All NTA Abhyas JEE Main PYQs