NTA Abhyas JEE Main2020MathematicsHyperbolaPractice
If the eccentricity of the hyperbola x 2 16 - y 2 b 2 = - 1 is 5 4 , then b 2 is equal to
Options
- A256 9
- B16 3
- C9
- D3
Correct answer
A. 256 9
Step-by-step solution
y 2 b 2 - x 2 16 = 1 For the hyperbola, e = 1 + 16 b 2 ⇒ 1 + 16 b 2 = 5 4 ⇒ b 2 = 256 9