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AIIMS 201925 May
Exam
AIIMS
Year
2019
Date
25 May
Subject
Chemistry
Chapter
Solid State

AIIMS 2019 · 25 May · Chemistry · Solid State

The number of tetrahedral voids present in 0.5 mole of h c p...

The number of tetrahedral voids present in 0.5 mole of hcph c p crystal structure are

Options

  1. A3.6×10233.6 \times 10^{23}
  2. B9×10239 \times 10^{23}
  3. C3.6×10243.6 \times 10^{24}
  4. D6.02×10236.02 \times 10^{23}

Correct answer

C. 3.6×10243.6 \times 10^{24}

Step-by-step solution

For hcp, Z=6Z=6 ∴\therefore Tetrahedral voids =2Z=2×6=12=2 Z=2 \times 6=12 Tetrahedral voids present in 0.5 mol=12×0.5 mol0.5 \mathrm{~mol}=12 \times 0.5 \mathrm{~mol} =6NA=6×6.02×1023=3.6×1024=6 N_A=6 \times 6.02 \times 10^{23}=3.6 \times 10^{24}
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