NTA Abhyas JEE Main2020MathematicsMatricesPractice
Consider the matrix A = 3 1 - 6 - 2 , then Ι + A 40 is equal to
Options
- AΙ + 2 38 A
- BΙ + 2 39 A
- CΙ + 2 40 + 1 A
- DΙ + 2 40 - 1 A
Correct answer
D. Ι + 2 40 - 1 A
Step-by-step solution
A 2 = 3 1 - 6 - 2 3 1 - 6 - 2 = 3 1 - 6 - 2 = A A 3 = A 4 = A 5 . . . . . . . . . = A 40 = A Ι + A 40 = Ι + 40 C 1 A + 40 C 2 A 2 . . . . . . . + 40 C 40 A 40 = Ι + A 40 C 1 + 40 C 2 . . . . . . . 40 C 40 = Ι + A 2 40 - 1