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AIIMS 201826 May
Exam
AIIMS
Year
2018
Date
26 May
Subject
Chemistry
Chapter
Solid State

AIIMS 2018 · 26 May · Chemistry · Solid State

In HCP of A, (1)/(3) of tetrahedral voids are occupied by B . What...

In HCP\mathrm{HCP} of A,13A, \frac{1}{3} of tetrahedral voids are occupied by BB. What is the formula of the compound?

Options

  1. AA2B3A_2 B_3
  2. BA3B2A_3 B_2
  3. CAB3A B_3
  4. DA2BA_2 B

Correct answer

B. A3B2A_3 B_2

Step-by-step solution

No. of atoms (A)=6(hcp)(A)=6(h c p), no. of BB atoms =13×12=4=\frac{1}{3} \times 12=4 Hence, the formula of the compound is A6B4A_6 B_4 or A3B2A_3 B_2.
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