The number of ordered pairs ( x , y ) satisfying the equations y = 2 sin ⁡ x a n d y = 5 x 2 + 2 x + 3 is/are

Step-by-step solution

2 sin ⁡ x = 5 x 2 + 2 x + 3 ⇒ 2 sin ⁡ x = 4 x 2 + x + 1 2 + 2 But, 2 sin ⁡ x ≤ 2 and 4 x 2 + x + 1 2 + 2 > 2 , so it has no solution