NTA Abhyas JEE Main2020MathematicsTrigonometric EquationsPractice
The equation t a n 4 x - 2 s e c 2 x + a 2 = 0 will have at least one solution, if
Options
- Aa ≤ 4
- Ba ≤ 2
- Ca ≤ 3
- Da > 2
Correct answer
C. a ≤ 3
Step-by-step solution
t a n 4 x - 2 s e c 2 x + a 2 = 0 t a n 4 x - 2 1 + t a n 2 x + a 2 = 0 t a n 4 x - 2 t a n 2 x + 1 = 3 - a 2 t a n 2 x - 1 2 ≥ 0 ⇒ 3 - a 2 ≥ 0 ⇒ a 2 - 3 ≤ 0 ⇒ a ≤ 3