NTA Abhyas 2020 · Mathematics · Trigonometric Ratios & Identities
C. 233\dfrac{2}{3\sqrt{3}}332
As sin2θ+cos2θ=1,sin^{2}\theta + cos^{2}\theta = 1,sin2θ+cos2θ=1,
⇒sin2θ+cos2θ2+cos2θ2=1⇒ sin^{2}\theta + \dfrac{cos^{2}\theta}{2} + \dfrac{cos^{2}\theta}{2} = 1⇒sin2θ+2cos2θ+2cos2θ=1Applying AM≥GM,AM \ge GM,AM≥GM, we havesin2θ+cos2θ2+cos2θ23≥(sin2θcos4θ4)13\dfrac{sin^{2}\theta + \dfrac{cos^{2}\theta}{2} + \dfrac{cos^{2}\theta}{2}}{3} \ge {\left(\dfrac{sin^{2}\theta cos^{4}\theta}{4}\right)}^{\dfrac{1}{3}}3sin2θ+2cos2θ+2cos2θ≥(4sin2θcos4θ)31⇒(13)3≥sin2θcos4θ4⇒ {\left(\dfrac{1}{3}\right)}^{3} \ge \dfrac{sin^{2}\theta cos^{4}\theta}{4}⇒(31)3≥4sin2θcos4θ
⇒(sinθ⋅cos2θ)2≤427⇒ \left(sin \theta ⋅ cos^{2}\theta\right)2 \le \dfrac{4}{27}⇒(sinθ⋅cos2θ)2≤274⇒sinθ⋅cos2θ≤233⇒ sin \theta ⋅ cos^{2}\theta \le \dfrac{2}{3\sqrt{3}}⇒sinθ⋅cos2θ≤332