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JEE Main 202624 JanuaryMorning Shift
Exam
JEE Main
Year
2026
Date
24 January
Shift
Morning Shift
Subject
Mathematics
Chapter
Trigonometric Ratios & Identities

JEE Main 2026 · 24 January · Morning Shift · Mathematics · Trigonometric Ratios & Identities

The value of 3 cosec 20^ - 20^ 20^ 40^ 60^ 80^ is equal to

The value of 3cosec⁡20∘−sec⁡20∘cos⁡20∘cos⁡40∘cos⁡60∘cos⁡80∘\frac{\sqrt{3} \operatorname{cosec} 20^{\circ}-\sec 20^{\circ}}{\cos 20^{\circ} \cos 40^{\circ} \cos 60^{\circ} \cos 80^{\circ}} is equal to

Options

  1. A16
  2. B32
  3. C64
  4. D12

Correct answer

C. 64

Step-by-step solution

Numerator:
3cosec⁡20°−sec⁡20°=3cos⁡20°−sin⁡20°sin⁡20°cos⁡20°\sqrt{3}\operatorname{cosec} 20° - \sec 20° = \frac{\sqrt{3}\cos 20° - \sin 20°}{\sin 20° \cos 20°}
3cos⁡20°−sin⁡20°=2\sqrt{3}\cos 20° - \sin 20° = 2\left(\frac{\sqrt{3}}{2}\cos 20° - \frac{1}{2}\sin 20°\right)<br><br>= 2\cos(20° + 30°) = 2\cos 50°<br>Sonumerator=<br>So numerator =\frac{2\cos 50°}{\sin 20° \cos 20°} = \frac{4\cos 50°}{\sin 40°} = 4<br>Denominator:<br><br>Denominator:<br>\cos 20° \cos 40° \cos 60° \cos 80°wherewhere\cos 60° = \frac{1}{2}<br>Usingproductformula:<br><br>Using product formula:<br>\sin 20° \cos 20° \cos 40° \cos 80° = \frac{1}{8}\sin 20°<br>Therefore<br>Therefore\cos 20° \cos 40° \cos 80° \cdot \frac{1}{2} = \frac{1}{16}<br>So,<br>So,\frac{4 \cdot \sin 20° \cos 20°}{\frac{1}{16}} = 64
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