JEE Main 202624 JanuaryMorning Shift
- Exam
- JEE Main
- Year
- 2026
- Date
- 24 January
- Shift
- Morning Shift
- Subject
- Mathematics
- Chapter
- Trigonometric Ratios & Identities
JEE Main 2026 · 24 January · Morning Shift · Mathematics · Trigonometric Ratios & Identities
The value of 3 cosec 20^ - 20^ 20^ 40^ 60^ 80^ is equal to
The value of is equal to
Options
- A16
- B32
- C64
- D12
Correct answer
C. 64
Step-by-step solution
Numerator:
\left(\frac{\sqrt{3}}{2}\cos 20° - \frac{1}{2}\sin 20°\right)= 2\cos(20° + 30°) = 2\cos 50°\frac{2\cos 50°}{\sin 20° \cos 20°} = \frac{4\cos 50°}{\sin 40°} = 4\cos 20° \cos 40° \cos 60° \cos 80°\cos 60° = \frac{1}{2}\sin 20° \cos 20° \cos 40° \cos 80° = \frac{1}{8}\sin 20°\cos 20° \cos 40° \cos 80° \cdot \frac{1}{2} = \frac{1}{16}\frac{4 \cdot \sin 20° \cos 20°}{\frac{1}{16}} = 64
\left(\frac{\sqrt{3}}{2}\cos 20° - \frac{1}{2}\sin 20°\right)= 2\cos(20° + 30°) = 2\cos 50°\frac{2\cos 50°}{\sin 20° \cos 20°} = \frac{4\cos 50°}{\sin 40°} = 4\cos 20° \cos 40° \cos 60° \cos 80°\cos 60° = \frac{1}{2}\sin 20° \cos 20° \cos 40° \cos 80° = \frac{1}{8}\sin 20°\cos 20° \cos 40° \cos 80° \cdot \frac{1}{2} = \frac{1}{16}\frac{4 \cdot \sin 20° \cos 20°}{\frac{1}{16}} = 64