Consider the general term
cos3xsinx.
We can rewrite this by multiplying and dividing by
2cosx:
2cos3xcosx2sinxcosx=2cos3xcosxsin2xUsing
sin2x=sin(3x−x)=sin3xcosx−cos3xsinx, we get:
2cos3xcosxsin3xcosx−cos3xsinx=21(cos3xsin3x−cosxsinx)=21(tan3x−tanx)Applying this identity to each term of
A:
cos9∘sin3∘=21(tan9∘−tan3∘)cos27∘sin9∘=21(tan27∘−tan9∘)cos81∘sin27∘=21(tan81∘−tan27∘)Adding these terms, the series telescopes:
A=21(tan9∘−tan3∘+tan27∘−tan9∘+tan81∘−tan27∘)A=21(tan81∘−tan3∘)We are given
B=tan81∘−tan3∘.
Substituting
B into the equation for
A:
A=21B⇒AB=2Answer:
2