NTA Abhyas 2020
- Exam
- NTA Abhyas
- Year
- 2020
- Subject
- Mathematics
- Chapter
- Trigonometric Ratios & Identities
NTA Abhyas 2020 · Mathematics · Trigonometric Ratios & Identities
Three positive acute angles α, β and γ satisfy the relation tan...
Three positive acute angles and satisfy the relation and cot \dfrac{\gamma}{2} = \dfrac{1}{2} \left(3tan \dfrac{\alpha}{2} + cot \dfrac{\alpha}{2}\right). Then, the value of\alpha + \beta + \gamma is
Options
- A
- B
- C
- D
Correct answer
A.
Step-by-step solution
We have,&
Now,
⇒ \tan \left(\dfrac{\alpha + \beta}{2}\right) = \dfrac{3}{2} \left( tan tan \dfrac{\beta}{2}\right)<br />=\dfrac{3}{2} tan tan cot = cot ⇒ \tan \left(\dfrac{\alpha + \beta}{2}\right) =\dfrac{\gamma}{2} = \dfrac{1}{tan \dfrac{\gamma}{2}}
⋅ tan
⇒ \alpha + \beta + \gamma = \pi$$
Now,
⇒ \tan \left(\dfrac{\alpha + \beta}{2}\right) = \dfrac{3}{2} \left( tan tan \dfrac{\beta}{2}\right)<br />=\dfrac{3}{2} tan tan cot = cot ⇒ \tan \left(\dfrac{\alpha + \beta}{2}\right) =\dfrac{\gamma}{2} = \dfrac{1}{tan \dfrac{\gamma}{2}}
⋅ tan
⇒ \alpha + \beta + \gamma = \pi$$