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NTA Abhyas 2020
Exam
NTA Abhyas
Year
2020
Subject
Physics
Chapter
Communication System

NTA Abhyas 2020 · Physics · Communication System

The area of the region covered by the TV broadcast, by a TV tower...

The area of the region covered by the TV broadcast, by a TV tower of 100m100m height is (Take, the radius of the earth, Re=6.4×106m{R}_{e} = 6.4 \times {10}^{6}m )

Options

  1. A12.8π×108km212.8 \pi \times {10}^{8}{km}^{2}
  2. B1.28π×103km21.28 \pi \times {10}^{3}{km}^{2}
  3. C0.64π×103km20.64 \pi \times {10}^{3}{km}^{2}
  4. D1.28×103km21.28 \times {10}^{3}{km}^{2}

Correct answer

B. 1.28π×103km21.28 \pi \times {10}^{3}{km}^{2}

Step-by-step solution

Given, the height of the tower,

h=100mh = 100m

The radius of the earth, Re=6.4×106m{R}_{e} = 6.4 \times {10}^{6}m

Since we know,

the area covered by the TV tower,

A=2πRehA = 2\pi{R}_{e}h

=2π×6.4×106×100= 2\pi \times 6.4 \times {10}^{6} \times 100

=12.8π×108m2= 12.8\pi \times {10}^{8}m^{2}

=1.28π×103km2= 1.28\pi \times {10}^{3}{km}^{2}
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