The maximum electron density in the ionosphere in the morning is 10 10 m - 3 . At noon time, it increases to 2 × 10 10 m - 3 . Find the ratio of critical frequency at noon and the critical frequency in the morning.

Step-by-step solution

Given, the maximum electron density in the morning N m a x = 10 10   m - 3 f c ' = 9 N m a x 1 / 2 = 9 10 10 1 / 2 Critical frequency f c ′ = 9 × 10 5 The maximum electron density at noon N m a x = 2 × 10 10   m - 3 Critical frequency f c ′ ′ = 9 × N m a x ′ 1 2 = 9 × 2 × 10 10 1 2 = 9 × 2 × 10 5 The ratio of critical frequency at noon and critical frequency in the morning. f c ′ ′ f c ′ = 9 × 2 × 10 5 9 × 10 5 Or