NTA Abhyas 2020
- Exam
- NTA Abhyas
- Year
- 2020
- Subject
- Physics
- Chapter
- Communication System
NTA Abhyas 2020 · Physics · Communication System
In optical communication system operating at 1200 nm, only 2% of...
In optical communication system operating at 1200 nm, only 2% of the source frequency is available for TV transmission having a bandwidth of 5 MHz. The number of TV channels that can be transmitted is
Options
- A2 million
- B10 million
- C0.1 million
- D1 million
Correct answer
D. 1 million
Step-by-step solution
The frequency optical communication
v = \dfrac{c}{λ}orv = \dfrac{3 × {10}^{8}}{1200 × {10}^{- 9}}
But only 2% of the source frequency is available for TV transmission
v^{′} = 2.5 × {10}^{14} × 2%
Or v^{′} = 2.5 × {10}^{14} × \dfrac{2}{100}
Or v^{′} = 5 × {10}^{12}Hz
∴ Numberofchannels = \dfrac{v^{′}}{bondwidth}
Or
v = \dfrac{c}{λ}orv = \dfrac{3 × {10}^{8}}{1200 × {10}^{- 9}}
But only 2% of the source frequency is available for TV transmission
v^{′} = 2.5 × {10}^{14} × 2%
Or v^{′} = 2.5 × {10}^{14} × \dfrac{2}{100}
Or v^{′} = 5 × {10}^{12}Hz
∴ Numberofchannels = \dfrac{v^{′}}{bondwidth}
Or