Consider the vernier callipers shown below. The instrument has no zero error. If $1m . s . d = 1mm$ and $7m . s . d = 8v . s . d$ , then what is the length (in $mm$ ) of the rod shown in the figure? [Given; the ${4}^{th}v . s . d$ coincides with $m . s . d$ ]

Question

Consider the vernier callipers shown below. The instrument has no zero error. If 1m . s . d = 1mm and 7m . s . d = 8v .

Quantrex Academy · Accepted Answer

Correct answer: 4.5

7m . s . d = 8v . s . d ⇒ 1v . s . d = (7)/(8)m . s . d ⇒ L . C = (1 - (7)/(8))mm = (1)/(8)mm Were M . S . R = 4mm V . S . R = 4 value = (4 + (4)((1)/(8)))mm = 4 .5 mm

Consider the vernier callipers shown below. The instrument has no...

Correct answer

Step-by-step solution

More from Experimental Physics