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The distance advanced by the screw of a screw gauge is 2   m m in 4 rotations. Its cap is divided into 50 divisions. There is no zero error. If the screw reads 3 divisions on the main scale and 32 divisions on the cap, then the diameter (in mm ) of the wire is

Correct answer

1.82

Step-by-step solution

p i t c h = 2 / 4 L C = 2 / 4 50 = . 01 m m d i a m e t e r = 3 × 0.5 + 32 × . 01 = 1.5 + . 32 = 1.82 m m

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