NTA Abhyas JEE Main2020PhysicsExperimental PhysicsPractice
Smallest division on the main scale of given Vernier calipers is 0.5 m m . Vernier scale has 25 divisions and these coincide with 24 main scale divisions. The least count of Vernier callipers is
Options
- A0.001 c m
- B0.002 c m
- C0.01 c m
- D0.02 c m
Correct answer
B. 0.002 c m
Step-by-step solution
25 V S D = 24 M S D 1 V S D = 24 25 M S D .......(i) The least count of Vernier calipers is L C = 1 M S D - 1 V S D = 1 M S D - 24 25 M S D = 1 25 M S D (using (i)) As 1 M S D = 0.5 m m (given) ∴ L C = 1 25 ( 0.5 m m ) = 0.02 m m = 0.002 c m