Let the end error on the LHS and RHS be equal to 1 cm. For the balance point at O, find out the % error in the value of X? (If the end error is 1 cm from both sides then it means the correct reading will become 10 cm + 1 cm from LHS and 90 cm + 1 cm from the RHS)

Step-by-step solution

x 9 0 = l ⁡ 1 l ⁡ 2 = 1 1 9 1 x = 1 1 9 1 9 0 x ′ 9 0 = 1 0 9 0 ⇒ x ′ = 1 0 ⇒ Δ x = 1 1 9 1 9 0 - 1 0 = 9 9 0 - 9 1 0 9 1 = 8 0 9 1 Δ x % = Δ x x × 1 0 0 = 8 0 9 1 9 9 0 9 1 × 1 0 0 = 8 0 0 9 9 % = 8.1 %