NTA Abhyas 2020
- Exam
- NTA Abhyas
- Year
- 2020
- Subject
- Physics
- Chapter
- Experimental Physics
NTA Abhyas 2020 · Physics · Experimental Physics
Let the end error on the LHS and RHS be equal to 1 cm. For the...
Let the end error on the LHS and RHS be equal to 1 cm. For the balance point at O, find out the % error in the value of X? (If the end error is 1 cm from both sides then it means the correct reading will become 10 cm + 1 cm from LHS and 90 cm + 1 cm from the RHS)
Options
- A4.2 %
- B8.1%
- C9.2%
- DNone
Correct answer
B. 8.1%
Step-by-step solution
\dfrac{{\text{x}}^{′}}{9 0} = \dfrac{1 0}{9 0}
\to {\text{x}}^{′} = 1 0
\to Δ \text{x} = \left(\dfrac{1 1}{9 1} \left(9 0\right) - 1 0\right)
Δ \text{x} \text{%} = \dfrac{Δ \text{x}}{\text{x}} × 1 0 0 = \dfrac{\dfrac{8 0}{9 1}}{\dfrac{9 9 0}{9 1}} × 1 0 0
= \dfrac{8 0 0}{9 9} \text{%}
= \text{8.1} \text{%}