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In an experiment on measurements of emf of a cell by a potentiometer, the balancing length for a cell of emf E and internal resistance r is found to be l . Now if another cell of emf E and internal resistance 2 r is connected in parallel to the first cell and balancing length determined, then the balancing length will be-

Options

  1. Al
  2. B2   l
  3. Cl 2
  4. D2 l 3

Correct answer

A. l

Step-by-step solution

Since potentiometer doesn't draw any current to measure the emf of the cell, the balancing length will remain the same. balancing length = l

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