NTA Abhyas JEE Main2020PhysicsRotational MotionPractice
A merry-go-round is at rest, pivoted on a frictionless axis. A child of mass m runs along the path tangential to the rim with speed v and jumps on to merry-go-round. If R is the radius of the merry-go-round and I is the moment of inertia, then the angular velocity of the merry-go-round and the child is
Options
- Am v R m R 2 + I
- Bm v R I
- Cm R 2 + I m v R
- DI m v R
Correct answer
A. m v R m R 2 + I
Step-by-step solution
By law of conservation of angular momentum mvR = I system ω ⇒ mvR = I + mR 2 ω ⇒ ω = mvR I + mR 2