NTA Abhyas JEE Main2020PhysicsRotational MotionPractice
A uniform ring is rotating about the vertical axis with angular velocity ω initially. A point insect ( S ) having the same mass as that of the ring starts walking from the lowest point P 1 and finally reaches the point P 2 (as shown in the figure). The final angular velocity of the ring is
Options
- Aω / 4
- Bω
- Cω / 2
- Dω / 3
Correct answer
D. ω / 3
Step-by-step solution
From the conservation of angular momentum 1 2 M R 2 ω = 1 2 MR 2 + MR 2 ω ´ ⇒ 1 2 MR 2 ω = 3 2 MR 2 ω ´ ⇒ ω ´ = ω 3