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The moment of inertia of a circular ring of mass 1 kg about an axis passing through its centre and perpendicular to its plane is 4 kg m 2 . The diameter of the ring is

Options

  1. A2   m
  2. B4   m
  3. C5   m
  4. D6   m

Correct answer

B. 4   m

Step-by-step solution

Moment of inertia of circular ring about an axis passing through its centre of mass and perpendicular to its plane I = M R 2 Here, I = 4   k g   m 2 ,   m = 1   k g R 2 = 4 1 = 4 or R = 2   m Therefore, diameter of ring = 4 m.

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