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NTA Abhyas JEE Main2020PhysicsRotational MotionPractice

A uniform rod of mass M 1 is hinged at its upper end. A particle of mass M 2 moving horizontally strikes the rod at its midpoint elastically. If the particle comes to rest after collision, then, Find the value of M 1 M 2

Options

  1. A3 4
  2. B4 3
  3. C2 3
  4. D3 2

Correct answer

A. 3 4

Step-by-step solution

Angular Momentum about Hinge L H = I H . ω ( I H = m 1 l 2 3 ) L H = M 2 v L 2 = M 1 L 2 3 ω ω = 3 M 2 v 2 M 1 L … 1 for e = 1 , v C M = v = ω L 2 … 2 ⇒ 2 v L = 3 M 2 v 2 M 1 L ⇒ M 1 M 2 = 3 4 = 0.75

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