NTA Abhyas JEE Main2020PhysicsRotational MotionPractice
A uniform solid sphere of mass M , radius R and having moment of inertia about an axis passing through center of mass is I , is recast into a uniform circular disc of thickness t , whose moment of inertia about an axis passing through its edge and perpendicular to its plane remains I . Then radius of the disc will be
Options
- AR 2 15
- B2 R 15
- C4 R 15
- DR 4
Correct answer
B. 2 R 15
Step-by-step solution
I = 2 5 M R 2 and ρ = 3 M 4 π R 3 For circular disc π r 2 × t ρ = M ⇒ π r 2 ⋅ t ⋅ 3 M 4 π R 3 = M ⇒ t = 4 π R 3 3 π r 2 = 4 R 3 3 r 2 ⇒ r 2 = 4 R 3 3 t 2 5 M R 2 = 3 2 M R 2 ⇒ 2 5 R 2 = 3 2 ⋅ 4 R 3 3 t ⇒ t = 5 R ⇒ r 2 ⋅ 3 ⋅ 5 R = 4 R 3 ⇒ r 2 = 4 R 2 15 ⇒ r = 2 R 15