A solid A B has NaCl type structure. The radius of A^ + is 100 pm . What is the radius of B^ - ?

Correct answer: A. 190.47 NaCl type structure is also called face centred cubic lattice. Here the radius ratio (r_c / r_a) ranges from 0.414 to 0.732 . aligned Radius ratio =(r_c)/(r_a)=& radius of cation radius of anion Radius of anion ( B^ - ) & = radius of A^ + radius ratio & =(100)/(0.414) to (100)/(0.732) & =241.5 to 136.6 . aligned

AIIMS 2001

Exam: AIIMS
Year: 2001
Subject: Chemistry
Chapter: Solid State

AIIMS 2001 · Chemistry · Solid State

A solid A B has NaCl type structure. The radius of A^ + is 100 pm ....

A solid

A B

has

\mathrm{NaCl}

type structure. The radius of

A^{+}

100 \mathrm{pm}

. What is the radius of

B^{-}

Options

A190.47
B540.13
C525
D78.12

Correct answer

A. 190.47

Step-by-step solution

\mathrm{NaCl}

type structure is also called face centred cubic lattice. Here the radius ratio

\left(r_c / r_a\right)

ranges from 0.414 to 0.732 .

\begin{aligned}\text{ Radius ratio }=\frac{r_c}{r_a}=& \frac{\text{ radius of cation }}{\text{ radius of anion }}\\ \Rightarrow \quad \text{ Radius of anion }\left( B^{-}\right) & =\frac{\text{ radius of } A^{+}}{\text{radius ratio }}\\ & =\frac{100}{0.414} \text{ to } \frac{100}{0.732}\\ & =241.5 \text{ to }136.6 . \end{aligned}

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