NTA Abhyas JEE Main2020PhysicsThermal Properties of MatterPractice
Liquids A and B are at 30   o C and 20   o C , respectively. When mixed in equal masses, the temperature of the mixture is found to be 26   o C , The specific heats of A and B are in the ratio of m : n , where m and n are integers, then find minimum value of m + n .
Correct answer
5
Step-by-step solution
At thermal equilibrium heat rejected by one liquid = heat accepted by other liquid m s A 30 – 26 = m s B 26 – 20 ⇒ 4 s A = 6 s B ∴ s A s B = 6 4 = 3 2 = m n ⇒ m + n = 3 + 2 = 5