A liquid A of mass 100 g at 100 ° C is added to 50 g of a liquid B at temperature 75 ° C , the temperature of the mixture becomes 90 ° C . Now if 100 g of liquid A at 100 ° C is added to 50 g of liquid B at 50 ° C , temperature of the mixture will be

Step-by-step solution

Heat loss will always be equal to heat gain. As per 1 s t condition, 100 × S A × ( 100 - 90 ) = 50 × S B × ( 90 - 75 )   ___ ( i ) As per 2 n d condition, 100 × S A ( 100 - θ ) = 50 × S B ( θ - 50 )   ___ ( ii ) Dividing ( ii ) by ( i ) , we get 100 - θ 100 - 90 = θ - 50 90 - 75 300 - 3 θ = 2 θ - 100 θ = 80 ° C