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NTA Abhyas 2020
Exam
NTA Abhyas
Year
2020
Subject
Physics
Chapter
Thermal Properties of Matter

NTA Abhyas 2020 · Physics · Thermal Properties of Matter

150g of water at 0 ° C is contained in a thermally insulated...

150g150g of water at 0°C0 ° C is contained in a thermally insulated container. Now the air from the vessel is pumped out adiabatically. A fraction of water gets converted into ice and the remaining evaporates at 0°C0 ° C itself. The mass of evaporated water will be closest to [Take the latent heat of vaporization of water, Lv=2.10×106Jkg−1{L}_{v} = 2. 10 \times {10}^{6}J{kg}^{- 1} and latent heat of fusion of water, Lf=3.36×105Jkg−1{L}_{f} = 3. 36 \times {10}^{5}J{kg}^{- 1}]

Options

  1. A20g20\text{g}
  2. B130g130g
  3. C35g35\text{g}
  4. D150g150g

Correct answer

A. 20g20\text{g}

Step-by-step solution

Let us assume the mass of the water evaporated is mm, then

mLv=(150−m)Lfm{L}_{v} = \left(150 - m\right){L}_{f}

m×2.1×106=(150−m)×3.36×105m \times 2. 1 \times {10}^{6} = \left(150 - m\right) \times 3. 36 \times {10}^{5}

On solving we get

m≈20gm \approx 20g

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