A clock that keeps correct time at 20 ° C , is subjected to 40 ° C . If the coefficient of linear expansion of the pendulum is 12 × 10 - 6 ° C - 1 , the time gained or lost, per day, is

Step-by-step solution

Time period, T = 2 π l g ∆ T T = 1 2 ∆ l l = 1 2 α ∆ θ = 1 2 × 12 × 10 − 6 × ( 40 − 20 ) = 12 × 10 − 5 ∆ T = T × 12 × 10 - 5 = 24 × 60 × 60 × 12 × 10 - 5 = 10.3     s     day − 1