NTA Abhyas JEE Main2020PhysicsThermal Properties of MatterPractice
The power radiated by a black-body is P 0 and it radiates maximum energy around the wavelength λ 0 . If the temperature of the black-body is now changed so that it radiates maximum energy around a wavelength 3 λ 0 4 , then the power radiated by it will be
Options
- A4 3 P 0
- B16 9 P 0
- C64 27 P 0
- D256 81 P 0
Correct answer
D. 256 81 P 0
Step-by-step solution
Let T 0 be the initial temperature of the black body ∴   λ 0 T 0 = b   (Wien's law) Power radiated, P 0 = C T 0 4 ,   where, C is constant. If T is new temperature of black body, then 3 λ 0 4 T = b = λ 0 T 0     o r     T = 4 3   T 0 Power radiated, P = C T 4 = C T 0 4 4 3 4 P = 256 81 P 0