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NTA Abhyas JEE Main2020PhysicsThermal Properties of MatterPractice

A point source of heat of power P is placed at the centre of a thin spherical shell of mean radius R . The material of the shell has thermal conductivity K . Calculate the thickness of the shell if the temperature difference between the outer and inner surfaces of the shell in steady-state is T .

Options

  1. A4 π R 2 KT 2 P
  2. B3 π R 4 KT P
  3. C4 π R 2 KT P
  4. D2 π R 2 KT 3 P

Correct answer

C. 4 π R 2 KT P

Step-by-step solution

Consider a concentric spherical shell of radius r and thickness d r as shown in diagram. The radial rate of flow of heat through this shell in steady state will be, H = d Q d t = - KA d θ d r [Negative sign is used because, with an increase in r , θ decreases.] Now as for spherical shell A = 4 π r 2 So H = - 4 π r 2 K d θ d r or ∫ a b d r r 2 = - 4 π K H ∫ θ 1 θ 2 d θ which on integration and simplification gives H = d Q d t = K 4 π a b θ 1 - θ

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