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NTA Abhyas JEE Main2020PhysicsThermal Properties of MatterPractice

A pendulum clock is 5 s fast at a temperature of 15 ° C and 10 s slow at a temperature of 30 ° C . At what temperature does it give the correct time? (take time interval = 24 hours )

Options

  1. A18   ° C
  2. B22 ° C
  3. C20 ° C
  4. D25   ° C

Correct answer

C. 20 ° C

Step-by-step solution

Δ t = 1 2 α Δ T × t ∴ 5 = 1 2 α T - 1 5 × 8 6 4 0 0 .........(i) And 1 0 = 1 2 α 3 0 - T × 8 6 4 0 0 ........(ii) Dividing both equations, 1 2 = T - 15 30 - T ⇒ 30 - T = 2 T - 30 ⇒ 3 T = 60 ⇒ T = 20 ° C

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