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A steel rod is 4 . 000   cm in diameter at 30   ° C . A brass ring has an interior diameter of 3 . 992   cm at 30   ° C . In order that the ring just slides onto the steel rod, the common temperature of the two should be α steel = 11 × 10 - 6 /   ° C   a n d   α brass = 19 × 10 - 6 /   ° C

Options

  1. A200   ° C
  2. B350   ° C
  3. C280   ° C
  4. D300   ° C

Correct answer

C. 280   ° C

Step-by-step solution

4 1 + 11 × 10 - 6 Δ T = 3.992   1 + 19 × 10 - 6 Δ T ⇒     0.008 = 31.848 × 10 - 6 ∆ T ⇒ ∆ T = 250   ° C

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