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A calorimeter contains 0 . 2 kg of water at 30 ° C , in which 0 . 1 kg of water at 60 ° C is added. The mixture is well stirred and the resulting temperature is found to be 35 ° C . The thermal capacity of the calorimeter is

Options

  1. A6300   J   K - 1
  2. B1260   J   K - 1
  3. C4200   J   K - 1
  4. D3200   J   K - 1

Correct answer

B. 1260   J   K - 1

Step-by-step solution

Let X be the thermal capacity of the calorimeter and specific heat of water = 4200   J   kg - 1   K - 1 . Heat lost by 0 . 1   kg of water = Heat gained by water in calorimeter + Heat gained by calorimeter ⇒             0 . 1   ×   4200   ×   ( 60   -   35 ) =   0 . 2   ×   4200   ×   ( 35   -   30 )   +   X ( 35   -   30 ) 10500 &#

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