NTA Abhyas JEE Main2020PhysicsThermal Properties of MatterPractice
The temperature gradient in the earth's crust is 32 ° C km - 1 and the mean conductivity of earth is 0.008 cal s - 1 cm - 1 ° C - 1 . Considering the earth to be a sphere of radius 6000 km , the loss of heat by the earth every day is about
Options
- A10 30   cal
- B10 40   cal
- C10 20   cal
- D10 18 cal
Correct answer
D. 10 18 cal
Step-by-step solution
∆ Q = K A ∆ T ∆ x ∆ t = 0.008 10 2 × 4   × 22 7 6 × 10 8 2 × 32 10 3 × 86400 ≈ 10 18   cal