NTA Abhyas JEE Main2020PhysicsThermal Properties of MatterPractice
Calculate the resulting temperature when 20 g of boiling water is poured into an ice-cold brass vessel (specific heat = 0.1 cal g - 1 ° C - 1 ) of mass 100 g .
Options
- A66 .66 ° C
- B6 .66 ° C
- C0 .66 ° C
- D50 ° C
Correct answer
A. 66 .66 ° C
Step-by-step solution
The general formula for final temperature is θ = m 1 s 1 θ 1 + m 2 s 2 θ 2 + … m 1 s 1 + m 2 s 2 + … In this problem θ = m 1 s 1 θ 1 + m 2 s 2 θ 2 m 1 s 1 + m 2 s 2 Here, m 1 = 20   g ,           m 2 = 100   g θ 1 = 100   ° C ,           θ 2 = 0   ° C s 1 = 1   cal   g - 1   ° C - 1 s 2 = 0.1   cal   g - 1   ° C - 1 ∴       &