An inverted bell, lying at the bottom of lake 47 . 6   m deep, has 50   cm 3 of air trapped in it. The bell is brought to the surface of the lake, then the volume of the trapped air will become [atmospheric pressure = 70   cm of Hg and density of Hg = 13 . 6   g   cm - 3 ]

Step-by-step solution

According to Boyle's law, pressure and volume are inversely proportional to each other i.e. p ∝ 1 v ⇒ P 1 V 1 = P 2 V 2 ⇒ ( P 0 + h ρ w g ) V 1 = P 0 V 2 ⇒ V 2 = ( 1 + h ρ w g P 0 ) V 1 V 2 = ( 1 + 47.6 * 1 * 1000 * 10 70 * 10 − 2 * 13.6 * 1000 * 10 ) [ A s P 2 = P 0 = 70 c m o f H g = 70 * 10 − 2 * 13.6 * 1000 * 10 ] ⇒ V 2 = 1 + 5 5 0 cm 3 = 3 0 0 cm 3