NTA Abhyas JEE Main2020PhysicsThermodynamicsPractice
An ideal gas undergoes the cyclic process abca as shown in the figure. The internal energy change of the gas along the path c a is − 180 J . The gas absorb 250 J of heat along the path a b and also absorbs 60 J of heat along the path bc . Find the work done by the gas along the path a b c
Options
- A130 J
- B140   J
- C120   J
- D100   J
Correct answer
A. 130 J
Step-by-step solution
Change in internal energy for a cyclic process is zero. Thus, ∆ U abc + ∆ U ca = 0 ∆ U abc = - ∆ U ca = 180   J ΔQ = ΔW + ΔU 250 + 60 = ΔW + 180 ΔW = 130   J