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A pendulum clock (fitted with a small heavy bob that is connected with a metal rod) is 3 seconds fast each day at a temperature of 15   ° C and 2 seconds slow at a temperature of 30   ° C . Find the temperature (in ° C ) at which it will show the correct time.

Correct answer

24.00

Step-by-step solution

Fractional loss of time per second = 1 2 α Δ T Therefore 1 2 α T 0 − 15 × ( 24 hrs ) = 3 and 1 2 α 30 − T 0 × ( 24 hrs ) = 2 on solving T 0 = 24 ° C

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