NTA Abhyas JEE Main2020PhysicsThermodynamicsPractice
Temperature and volume curves are drawn for two thermodynamic processes. For the first process, it is a straight line and for the second, it is a rectangular hyperbola. The ratio of work done in the first process to the work done in the second process is
Options
- A2:1
- B3:1
- C4:1
- D3:2
Correct answer
A. 2:1
Step-by-step solution
The first process is a constant pressure process, hence w 1 = nR(2T 0 - T 0 ) = nRT 0 The equation for the second process is T = c V Hence, P = nRT V = nRc V 2 ∴ w = ∫ V 0 2 V 0 PdV = nRT 0 2 ∴ w 1 w 2 = 2 : 1 ∴ 2 : 1