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A Carnot engine, having an efficiency of η = 1 / 10 as a heat engine, is used as a refrigerator. If the work done on the system is 10 J , the amount of energy absorbed from the reservoir at a lower temperature is

Options

  1. A99   J
  2. B90   J
  3. C1   J
  4. D100   J

Correct answer

B. 90   J

Step-by-step solution

Relation between coefficient of performance and efficiency of refrigerator is β = 1 - η η ∴   β = 1 - 1 10 1 10 = 9 Coefficient of performance, β = Heat   absorbed ( Q 2 ) Work   done   ( W ) ⇒ 9 = Q 2 10 Q 2 = 90   J

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