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One mole of a diatomic gas undergoes a process P = P 0 [ 1 + ( V / V 0 ) 3 ] , where P 0 and V 0 are constants. The translational kinetic energy of the gas when V = V 0 is given by

Options

  1. A5 P 0 V 0 4
  2. B3 P 0 V 0 2
  3. C35 P 0 V 0 2
  4. D5 P 0 V 0 2

Correct answer

B. 3 P 0 V 0 2

Step-by-step solution

P = P 0 1 + V / V 0 3 = P 0 2 T = P 0 V 0 2 R Therefore, translational kinetic energy is equal to 3 2 RT = 3 R 2 P 0 V 0 2 R = 3 P 0 V 0 4

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