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Temperature of an ideal gas is 300 K . The final temperature of the gas when its volume changes from V to 2 V in the process p = αV (here α is a positive constant) is

Options

  1. A900 K
  2. B1200 K
  3. C300   K
  4. D500   K

Correct answer

B. 1200 K

Step-by-step solution

The given relation is p ∝ V Therefore, p ∝ V When V changes from V to 2 V , pressure p is also doubled For an ideal gas, pV T = constant ∴ T ∝ pV . Hence, T becomes 2 × 2 = 4 times T = 4 × 300 K = 1200 K

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