NTA Abhyas JEE Main2020PhysicsThermodynamicsPractice
In the given figure the area of the frictionless piston is 1 m 2 and it is being held in equilibrium by an external force. Now the external force is slowly removed and heat is supplied to the gas due to which the piston displaces by L 2 where L = 1 m . The natural length of the ideal springs is L = 1 m . Spring constant is given as K = 100 N m - 1 . The pressure of the gas in the final situation is
Options
- A50   N   m - 2  
- B100 N m - 2
- C200   N   m - 2  
- D400   N   m - 2  
Correct answer
B. 100 N m - 2
Step-by-step solution
In the case of equilibrium, net force on the piston becomes zero. So, PA - Kx = Kx ⇒ P = 2 Kx A = 2 × 100 1 × 1 2 = 100   N / m 2