NTA Abhyas JEE Main2020PhysicsThermodynamicsPractice
One mole of an ideal diatomic gas is taken through a process whose P - V diagram is shown in the figure. The work done by the gas is
Options
- AπP 0 V 0 + 2 P 0 V 0
- BπP 0 V 0 2 + P 0 V 0
- C2 πP 0 V 0 + P 0 V 0
- DπP 0 V 0 2 + P 0 V 0
Correct answer
B. πP 0 V 0 2 + P 0 V 0
Step-by-step solution
Work done = Area under the curve = P 0 V 0 + π 4 2 P 0 V 0