NTA Abhyas JEE Main2020PhysicsThermodynamicsPractice
An ideal Carnot's engine works between 227 ° C and 57 ° C . The efficiency of the engine will be
Options
- A22 %
- B34 %
- C55 %
- D13.5 %
Correct answer
B. 34 %
Step-by-step solution
T 1 = 227 ° C = ( 227 + 273 ) K = 500 K T 2 = 57 ° C = ( 57 + 273 ) K = 330 K Efficiency of Carnot's engine, η = 1 - T 2 T 1 = 1 - 330 500 = 0.34 or η = 34 %