NTA Abhyas JEE Main2020PhysicsThermodynamicsPractice
The temperature of 5 moles of a gas at constant volume is changed from 100 ° C to 120 ° C . The change in internal energy is 80 J . The total heat capacity of the gas at constant volume (in J K - 1 ) is
Options
- A8
- B4
- C0.8
- D0.4
Correct answer
B. 4
Step-by-step solution
Number of moles n = 5   mol ,      T 1 = 100   ° C T 2 = 120   ° C ,    ∆ U = 80   J Rise in temperature ∆ T = 120 - 100 = 20   ° C ∆ U = m s ∆ T 80 = 5 × M 0 × s × 20 , where M 0 is the molar mass The heat capacity is C = 5 M 0 s = 4   J   K - 1