NTA Abhyas JEE Main2020PhysicsThermodynamicsPractice
Carbon monoxide is carried around a closed cyclic process a b c , in which b c is an isothermal process, as shown in the diagram. The gas absorbs 7000 J of heat as its temperature is increased from 300 K to 1000 K in going from a to b . The quantity of heat ejected by the gas during the process c a is
Options
- A4200   J
- B500   J
- C9000   J
- D9800   J
Correct answer
D. 9800   J
Step-by-step solution
Δ Q ab = + 7 0 0 0 = μ  C v 1 0 0 0 - 3 0 0 ...(i) For the process c a : T a = 3 0 0 K , T c = T b = 1 0 0 0 K Δ Q ca = μ  C p 3 0 0 - 1 0 0 0 = - μ  C p × 7 0 0 = - μ C v + R 7 0 0 ...(ii) For carbon monoxide: T a = 3 0 0 K , T c = T h = 1 0 0 0 K Δ Q ca = μ  C p 3 0 0 - 1 0 0 0 = - μ  C p × 7 0 0 = - μ C v + R 7 0 0 For carbon monoxide: γ = 7 5 C v = R γ - 1 = R 7 5 - 1 = 5 R 2 ...(iii) Hence, from Eq. (i) 7 0 0 0 =