NTA Abhyas JEE Main2020PhysicsThermodynamicsPractice
For two thermodynamic process temperature and volume, diagrams are drawn. In the first process, it is a straight line having initial and final coordinates as V 0 , T 0 and 2 V 0 ,   2 T 0 , whereas in second process it is a rectangular hyperbola having initial and final coordinates (V 0 , T 0 ) and (2V 0 , T 0 /2). Then the ratio of work done in the two processes must be
Options
- A1   :   2
- B2   :   1
- C1   :   1
- DNone of these
Correct answer
B. 2   :   1
Step-by-step solution
The first process is the constant pressure process Hence, w 1   =   n R ( 2 T 0   -   T 0 )   =   n R T 0 Equation of the second process is T = c V Hence, P = nRT V = nRc V 2 ∴     w = ∫ V 0 2 V 0 PdV = nRT 0 2 ∴    w 1 w 2 = 2  :  1